Electrochemistry: explain question

A voltaic cell is constructed by connecting a $\ce{Pb(s)|Pb^{2+}(aq)}$ half-cell to an $\ce{Ag(s)|Ag^{+}(aq)}$ half-cell. The standard electrode potentials are:

$$\ce{Pb^{2+}(aq) + 2e- -> Pb(s)} \quad E^\circ = -0.13\text{ V}$$ $$\ce{Ag^{+}(aq) + e- -> Ag(s)} \quad E^\circ = +0.80\text{ V}$$

Explain the polarity of the electrodes, the direction of electron flow in the external circuit, and identify the species that is oxidised and reduced. Construct the overall redox equation for the cell reaction.