Electrochemistry: compare question

Chlorine is bubbled into cold dilute aqueous sodium hydroxide, forming sodium chloride and sodium chlorate(I).

Reaction 1: $\ce{Cl2 + 2NaOH -> NaCl + NaClO + H2O}$

With hot concentrated aqueous sodium hydroxide, the product is sodium chlorate(V) instead.

Reaction 2: $\ce{3Cl2 + 6NaOH -> 5NaCl + NaClO3 + 3H2O}$

Compare the redox behaviour of chlorine in these two reactions. For each reaction, use oxidation numbers and electron transfer to identify the species that is oxidised and the species that is reduced, give the oxidation number of chlorine in each chlorine-containing product using a Roman numeral where appropriate, and state whether chlorine acts as an oxidising agent, a reducing agent, or both.